regexp.input.step (method)

16 uses

	regexp (current package)
		backtrack.go#L207: 			r, width := i.step(pos)
		backtrack.go#L216: 			r, width := i.step(pos)
		backtrack.go#L225: 			r, width := i.step(pos)
		backtrack.go#L234: 			r, width := i.step(pos)
		backtrack.go#L355: 			_, width = i.step(pos)
		exec.go#L187: 	r, width = i.step(pos)
		exec.go#L189: 		r1, width1 = i.step(pos + width)
		exec.go#L214: 				r, width = i.step(pos)
		exec.go#L215: 				r1, width1 = i.step(pos + width)
		exec.go#L237: 			r1, width1 = i.step(pos + width)
		exec.go#L419: 	r, width = i.step(pos)
		exec.go#L421: 		r1, width1 = i.step(pos + width)
		exec.go#L439: 		r, width = i.step(pos)
		exec.go#L440: 		r1, width1 = i.step(pos + width)
		exec.go#L497: 			r1, width1 = i.step(pos + width)
		regexp.go#L373: 	step(pos int) (r rune, width int) // advance one rune

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